14*10+81=x^2

Solution for 14*10+81=x^2 equation:

14*10+81=x^2

We move all terms to the left:

14*10+81-(x^2)=0

We add all the numbers together, and all the variables

-1x^2+221=0

a = -1; b = 0; c = +221;
Δ = b2-4ac
Δ = 02-4·(-1)·221
Δ = 884
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{884}=\sqrt{4*221}=\sqrt{4}*\sqrt{221}=2\sqrt{221}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{221}}{2*-1}=\frac{0-2\sqrt{221}}{-2}
=-\frac{2\sqrt{221}}{-2}
=-\frac{\sqrt{221}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{221}}{2*-1}=\frac{0+2\sqrt{221}}{-2}
=\frac{2\sqrt{221}}{-2}
=\frac{\sqrt{221}}{-1}
$